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2.5x^2-25x+60=0
a = 2.5; b = -25; c = +60;
Δ = b2-4ac
Δ = -252-4·2.5·60
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5}{2*2.5}=\frac{20}{5} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5}{2*2.5}=\frac{30}{5} =6 $
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